This is “Appendix G: Physical Constants and Conversion Factors”, appendix 7 from the book Principles of General Chemistry (v. 1.0M).
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Selected Physical Constants | |
---|---|
Atomic mass unit | 1 amu = 1.6605389 × 10^{−24} g |
1 g = 6.022142 × 10^{23} amu | |
Avogadro’s number | N = 6.022142 × 10^{23}/mol |
Boltzmann’s constant | k = 1.380651 × 10^{−23} J/K |
Charge on electron | e = 1.6021765 × 10^{−19} C |
Faraday’s constant | F = 9.6485338 × 10^{4} C/mol |
Gas constant | R = 0.0820575 (L atm)/(mol K) |
= 8.31447 J/(mol K) | |
Mass of electron | m_{e} = 5.485799 × 10^{−4} amu |
= 9.109383 × 10^{−28} g | |
Mass of neutron | m_{n} = 1.0086649 amu |
= 1.6749273 × 10^{−24} g | |
Mass of proton | m_{p} = 1.0072765 amu |
= 1.6726217 × 10^{−24} g | |
Pi | π = 3.1415927 |
Planck’s constant | h = 6.626069 × 10 ^{−34}J s |
Speed of light (in vacuum) | c = 2.99792458 × 10^{8} m/s (exact) |
Useful Conversion Factors and Relationships | |
---|---|
Length | Energy (derived) |
Si unit: meter (m) | Si unit: joule (J) |
$\begin{array}{c}\text{1km}=0.\text{62137mi}\\ \text{1mi}=\text{528}0\text{ft}\\ =\text{1}.\text{6}0\text{93km}\\ \text{1m}=\text{1}.0\text{936yd}\\ \text{1in}=\text{2}.\text{54cm}\left(\text{exact}\right)\\ \text{1cm}=0.\text{3937}0\text{in}.\\ \text{1\xc5}=\text{1}{0}^{-\text{1}0}\text{m}\end{array}$ | $\begin{array}{c}\text{1J}=\text{1N}\bullet \text{m}=\text{1}\left(\text{kg}\bullet {\text{m}}^{\text{2}}\right)/{\text{s}}^{\text{2}}\\ \text{1J}=0.\text{239}0\text{cal}\\ =\text{1V}\times \text{1C}\\ \text{1cal}=\text{4}.\text{184J}\left(\text{exact}\right)\\ \text{1eV}=\text{1}.\text{6}0\text{2}\times \text{1}{0}^{-\text{19}}\text{J}\end{array}$ |
Mass | Pressure (derived) |
SI unit: kilogram (kg) | SI unit: pascal (Pa) |
$\begin{array}{c}\text{1kg}=\text{2}.\text{2}0\text{46lb}\\ \text{1lb}=\text{453}.\text{59g}\\ =\text{16oz}\end{array}$ | $\begin{array}{l}\text{1Pa}=\text{1N}/{\text{m}}^{\text{2}}\\ =\text{1kg}/\left(\text{m}\bullet {\text{s}}^{\text{2}}\right)\\ \text{1atm}=\text{101,325Pa}\\ =\text{76}0\text{torr}\\ =\text{14}.\text{7}0\text{lb}/{\text{in}}^{\text{2}}\\ \text{1bar}=\text{1}{0}^{\text{5}}\text{Pa}\end{array}$ |
Temperature | Volume (derived) |
Si unit: kelvin (K) | SI unit: cubic meter (m ^{3} ) |
$\begin{array}{c}0\text{K}=-\text{273}.\text{15}\xb0\text{C}\\ =\text{459}.\text{67}\xb0\text{F}\\ \text{K}=\xb0\text{C}+\text{273}.\text{15}\xb0\text{C}\\ \xb0\text{C}=\frac{5}{9}\left(\xb0\text{F}-\text{32}\xb0\right)\\ \xb0\text{F}=\frac{9}{5}\xb0\text{C}+\text{32}\end{array}$ | $\begin{array}{c}\text{1L}=\text{1}{0}^{-\text{3}}{\text{m}}^{\text{3}}\\ ={\text{1dm}}^{\text{3}}\\ =\text{1}{0}^{\text{3}}{\text{cm}}^{\text{3}}\\ \text{1gal}=\text{4qt}\\ =\text{3}.\text{7854L}\\ {\text{1cm}}^{\text{3}}=\text{1mL}\end{array}$ |